0=-16t^2-96t-10

Solution for 0=-16t^2-96t-10 equation:

0=-16t^2-96t-10

We move all terms to the left:

0-(-16t^2-96t-10)=0

We add all the numbers together, and all the variables

-(-16t^2-96t-10)=0

We get rid of parentheses

16t^2+96t+10=0

a = 16; b = 96; c = +10;
Δ = b2-4ac
Δ = 962-4·16·10
Δ = 8576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8576}=\sqrt{64*134}=\sqrt{64}*\sqrt{134}=8\sqrt{134}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-8\sqrt{134}}{2*16}=\frac{-96-8\sqrt{134}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+8\sqrt{134}}{2*16}=\frac{-96+8\sqrt{134}}{32}
$